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LE ROCHEREAU

New Aquitaine · FRANCE (FR) · 46.71°N / 0.15°E

75
ADM1 · ID GeoNames 3,002,311

Le Rochereau is a city in France with a population of 633. It sits at 46.71/0.15, runs on Europe/Paris, is 0 km from Champigny-le-Sec.

Population 633
Place Type Populated Place
Elevation n/a
Timezone Europe/Paris

All facts

fields
Country
France
Subdivision
New Aquitaine
Coords
46.71°N / 0.15°E
UTC offset
+1
DST
Observed

Proximity

nearest 10 · within 50 km
N Champigny-le-Sec New Aquitaine 848 1.0 km
E Charrais New Aquitaine 783 3.8 km
E Neuville-de-Poitou New Aquitaine 4,338 7.4 km
S Vouillé New Aquitaine 2,986 7.5 km
S Chiré-en-Montreuil New Aquitaine 849 7.9 km
SW Ayron New Aquitaine 1,014 8.0 km
E Chabournay New Aquitaine 769 8.0 km
N Mirebeau New Aquitaine 2,408 8.9 km
SE Cissé New Aquitaine 2,115 8.9 km
NE Thurageau New Aquitaine 744 9.5 km

Air access

nearby

FAQ

3 questions
What is the population of Le Rochereau?
633 people, per GeoNames.
Which timezone is Le Rochereau in?
Europe/Paris.
Which country is Le Rochereau in?
France (FR).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/3002311

{
  "data": {
    "id": 3002311,
    "name": "Le Rochereau",
    "ascii_name": "Le Rochereau",
    "country_code": "FR",
    "population": 633,
    "elevation": null,
    "timezone_id": "Europe/Paris",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 46.70772,
    "longitude": 0.1537
  }
}
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