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ARAULÍ

El Paraíso Department · HONDURAS (HN) · 13.97°N / 86.54°W

07
ADM1 · ID GeoNames 3,615,108

Araulí is a city in Honduras with a population of 1,160. It sits at 13.97/-86.54, runs on America/Tegucigalpa, is 4 km from El Pescadero.

Population 1,160
Place Type Populated Place
Elevation n/a
Timezone America/Tegucigalpa

All facts

fields
Country
Honduras
Subdivision
El Paraíso Department
Coords
13.97°N / 86.54°W
UTC offset
-6
DST
Observed

Proximity

nearest 10 · within 50 km
S El Pescadero El Paraíso Department 909 4.4 km
NW Danlí El Paraíso Department 44,799 7.9 km
W San Matías El Paraíso Department 1,251 9.6 km
S Cuyalí El Paraíso Department 1,572 9.9 km
NE El Benque El Paraíso Department 1,101 10.8 km
S El Paraíso El Paraíso Department 18,779 11.8 km
NE San Diego El Paraíso Department 1,306 12.0 km
E El Obraje El Paraíso Department 1,703 12.4 km
W Jacaleapa El Paraíso Department 2,578 14.0 km
SW Santa Cruz El Paraíso Department 1,430 15.1 km

FAQ

3 questions
What is the population of Araulí?
1,160 people, per GeoNames.
Which timezone is Araulí in?
America/Tegucigalpa.
Which country is Araulí in?
Honduras (HN).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/3615108

{
  "data": {
    "id": 3615108,
    "name": "Araulí",
    "ascii_name": "Arauli",
    "country_code": "HN",
    "population": 1160,
    "elevation": null,
    "timezone_id": "America/Tegucigalpa",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 13.973,
    "longitude": -86.545
  }
}
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