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SVETI IVAN ZELINA

Zagreb County · CROATIA (HR) · 45.96°N / 16.24°E

20
ADM1 · ID GeoNames 3,186,604

Sveti Ivan Zelina is a city in Croatia with a population of 2,583. It sits at 45.96/16.24, runs on Europe/Zagreb, is 0 km from Biškupec Zelinski.

Population 2,583
Place Type District Capital
Elevation n/a
Timezone Europe/Zagreb

All facts

fields
Country
Croatia
Subdivision
Zagreb County
Coords
45.96°N / 16.24°E
UTC offset
+1
DST
Observed

Proximity

nearest 10 · within 50 km
W Biškupec Zelinski Zagreb County 889 0.8 km
S Donja Zelina Zagreb County 786 5.7 km
SE Rakovec Zagreb County 226 6.4 km
SW Moravče Zagreb 602 6.6 km
SW Blaškovec Zagreb County 559 6.8 km
W Glavnica Donja Zagreb 506 7.9 km
N Bedenica Zagreb County 483 8.2 km
SW Adamovec Zagreb 900 8.7 km
S Lužan Zagreb 708 9.1 km
SW Blaguša Zagreb 524 9.4 km

Air access

nearby

FAQ

3 questions
What is the population of Sveti Ivan Zelina?
2,583 people, per GeoNames.
Which timezone is Sveti Ivan Zelina in?
Europe/Zagreb.
Which country is Sveti Ivan Zelina in?
Croatia (HR).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/3186604

{
  "data": {
    "id": 3186604,
    "name": "Sveti Ivan Zelina",
    "ascii_name": "Sveti Ivan Zelina",
    "country_code": "HR",
    "population": 2583,
    "elevation": null,
    "timezone_id": "Europe/Zagreb",
    "feature_class": "P",
    "feature_code": "PPLA2",
    "latitude": 45.95985,
    "longitude": 16.24327
  }
}
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