SAN ANDRÉS TEOTILALPAM

Oaxaca · MEXICO (MX) · 17.95°N / 96.66°W

ADM1 · ID GeoNames 3,519,913

San Andrés Teotilalpam is a city in Mexico with a population of 1,429. It sits at 17.95/-96.66, runs on America/Mexico_City, is 5 km from Teutila.

Population 1,429

Place Type Populated Place

Elevation n/a

Timezone America/Mexico_City

All facts

fields

Country: Mexico
Subdivision: Oaxaca
Coords: 17.95°N / 96.66°W
UTC offset: -6
DST: Observed

Proximity

nearest 10 · within 50 km

NW Teutila Oaxaca 1,030 5.9 km

W Santa María Tlalixtac Oaxaca 852 8.6 km

N San Bartolomé Ayautla Oaxaca 2,858 8.8 km

SW San Alejo el Progreso Oaxaca 614 10.4 km

NW Chiquihuitlán de Benito Juárez Oaxaca 1,877 10.4 km

S San Juan Sautla Oaxaca 1,239 10.8 km

NW La Soledad Piedra Ancha Oaxaca 572 11.2 km

NE Loma Naranja Oaxaca 565 11.5 km

SE San Juan Bautista Tlacoatzintepec Oaxaca 1,103 12.8 km

S Santiago Quetzalapa Oaxaca 507 13.3 km

FAQ

3 questions

What is the population of San Andrés Teotilalpam?: 1,429 people, per GeoNames.
Which timezone is San Andrés Teotilalpam in?: America/Mexico_City.
Which country is San Andrés Teotilalpam in?: Mexico (MX).

Get this page as JSON

no auth

cURL 200 OK

$ curl https://api.cityapi.org/v1/cities/3519913

{
  "data": {
    "id": 3519913,
    "name": "San Andrés Teotilalpam",
    "ascii_name": "San Andres Teotilalpam",
    "country_code": "MX",
    "population": 1429,
    "elevation": null,
    "timezone_id": "America/Mexico_City",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 17.95414,
    "longitude": -96.65607
  }
}