SAN ANTONIO ARRAZOLA

Oaxaca · MEXICO (MX) · 17.04°N / 96.79°W

ADM1 · ID GeoNames 3,532,726

San Antonio Arrazola is a city in Mexico with a population of 1,113. It sits at 17.04/-96.79, runs on America/Mexico_City, is 1 km from San Francisco Javier.

Population 1,113

Place Type Populated Place

Elevation n/a

Timezone America/Mexico_City

All facts

fields

Country: Mexico
Subdivision: Oaxaca
Coords: 17.04°N / 96.79°W
UTC offset: -6
DST: Observed

Proximity

nearest 10 · within 50 km

SE San Francisco Javier Oaxaca 1,162 1.8 km

SE El Paraíso Oaxaca 623 2.1 km

N Loma Bonita (Paraje Jagüey) Oaxaca 699 2.7 km

N La Cañada Oaxaca 1,033 3.6 km

NW San Pedro Ixtlahuaca Oaxaca 2,751 4.0 km

SE Cruz Blanca Oaxaca 985 4.1 km

SE Lomas de San Juan Oaxaca 901 4.7 km

S Cuilápam de Guerrero Oaxaca 12,360 4.9 km

NW San Andrés Ixtlahuaca Oaxaca 1,041 5.2 km

E Santa Cruz Xoxocotlán Oaxaca 67,086 6.0 km

Air access

nearby

OAX

Xoxocotlán International Airport

Large airport

8.2 km

FAQ

3 questions

What is the population of San Antonio Arrazola?: 1,113 people, per GeoNames.
Which timezone is San Antonio Arrazola in?: America/Mexico_City.
Which country is San Antonio Arrazola in?: Mexico (MX).

Get this page as JSON

no auth

cURL 200 OK

$ curl https://api.cityapi.org/v1/cities/3532726

{
  "data": {
    "id": 3532726,
    "name": "San Antonio Arrazola",
    "ascii_name": "San Antonio Arrazola",
    "country_code": "MX",
    "population": 1113,
    "elevation": null,
    "timezone_id": "America/Mexico_City",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 17.03972,
    "longitude": -96.79034
  }
}