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SAN FRANCISCO CHINDÚA

Oaxaca · MEXICO (MX) · 17.43°N / 97.31°W

20
ADM1 · ID GeoNames 3,519,282

San Francisco Chindúa is a city in Mexico with a population of 756. It sits at 17.43/-97.31, runs on America/Mexico_City, is 3 km from San Pedro Topiltepec.

Population 756
Place Type District Capital
Elevation n/a
Timezone America/Mexico_City

All facts

fields
Country
Mexico
Subdivision
Oaxaca
Coords
17.43°N / 97.31°W
UTC offset
-6
DST
Observed

Proximity

nearest 10 · within 50 km
W San Pedro Topiltepec Oaxaca 174 3.4 km
N Santiago Tillo Oaxaca 388 3.6 km
NE San Juan Sayultepec Oaxaca 501 4.0 km
SW Santo Domingo Tlatayápam Oaxaca 147 4.3 km
E San Mateo Etlatongo Oaxaca 427 4.4 km
NE San Andrés Sinaxtla Oaxaca 580 5.5 km
SE San Miguel Tecomatlán Oaxaca 210 6.0 km
SW San Francisco Nuxaño Oaxaca 362 6.3 km
SW Magdalena Yodocono de Porfirio Díaz Oaxaca 870 6.7 km
W Santiago Nejapilla Oaxaca 192 6.7 km

FAQ

3 questions
What is the population of San Francisco Chindúa?
756 people, per GeoNames.
Which timezone is San Francisco Chindúa in?
America/Mexico_City.
Which country is San Francisco Chindúa in?
Mexico (MX).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/3519282

{
  "data": {
    "id": 3519282,
    "name": "San Francisco Chindúa",
    "ascii_name": "San Francisco Chindua",
    "country_code": "MX",
    "population": 756,
    "elevation": null,
    "timezone_id": "America/Mexico_City",
    "feature_class": "P",
    "feature_code": "PPLA2",
    "latitude": 17.42873,
    "longitude": -97.31218
  }
}
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