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SAN FRANCISCO DEL MAR VIEJO

Oaxaca · MEXICO (MX) · 16.23°N / 94.63°W

20
ADM1 · ID GeoNames 3,519,274

San Francisco del Mar Viejo is a city in Mexico with a population of 4,033. It sits at 16.23/-94.63, runs on America/Mexico_City, is 11 km from Cerro Grande.

Population 4,033
Place Type Populated Place
Elevation n/a
Timezone America/Mexico_City

All facts

fields
Country
Mexico
Subdivision
Oaxaca
Coords
16.23°N / 94.63°W
UTC offset
-6
DST
Observed

Proximity

nearest 10 · within 50 km
NE Cerro Grande Oaxaca 548 11.5 km
NE Santa Rita (Santa Rita del Mar) Oaxaca 539 12.9 km
N Huamúchil Oaxaca 1,828 15.7 km
NW San Dionisio del Mar Oaxaca 3,140 16.8 km
NE San Francisco del Mar Oaxaca 4,724 17.4 km
E 20 de Noviembre (El Morro) Oaxaca 888 17.5 km
NE San Francisco Ixhuatan Oaxaca 5,408 20.7 km
W Santa María del Mar Oaxaca 771 24.0 km
NE Reforma de Pineda Oaxaca 2,671 26.5 km
E Rincón de Juárez Oaxaca 941 30.2 km

FAQ

3 questions
What is the population of San Francisco del Mar Viejo?
4,033 people, per GeoNames.
Which timezone is San Francisco del Mar Viejo in?
America/Mexico_City.
Which country is San Francisco del Mar Viejo in?
Mexico (MX).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/3519274

{
  "data": {
    "id": 3519274,
    "name": "San Francisco del Mar Viejo",
    "ascii_name": "San Francisco del Mar Viejo",
    "country_code": "MX",
    "population": 4033,
    "elevation": null,
    "timezone_id": "America/Mexico_City",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 16.23185,
    "longitude": -94.63297
  }
}
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