SAN FRANCISCO TUTEPETONGO

Oaxaca · MEXICO (MX) · 17.72°N / 96.88°W

ADM1 · ID GeoNames 3,519,247

San Francisco Tutepetongo is a city in Mexico with a population of 694. It sits at 17.72/-96.88, runs on America/Mexico_City, is 5 km from San José del Chilar.

Population 694

Place Type Populated Place

Elevation n/a

Timezone America/Mexico_City

All facts

fields

Country: Mexico
Subdivision: Oaxaca
Coords: 17.72°N / 96.88°W
UTC offset: -6
DST: Observed

Proximity

nearest 10 · within 50 km

W San José del Chilar Oaxaca 690 6.0 km

NW Tomellín Oaxaca 672 9.7 km

N Santos Reyes Pápalo Oaxaca 2,221 10.0 km

NW San Pedro Chicozapotes Oaxaca 884 10.1 km

NE San Pedro Cuyaltepec Oaxaca 665 11.4 km

NE Santa María Pápalo Oaxaca 1,593 11.6 km

NW Valerio Trujano Oaxaca 869 12.3 km

NW Cuicatlan Oaxaca 3,908 12.7 km

N Concepción Pápalo Oaxaca 674 13.9 km

W San Pedro Jaltepetongo Oaxaca 458 16.7 km

FAQ

3 questions

What is the population of San Francisco Tutepetongo?: 694 people, per GeoNames.
Which timezone is San Francisco Tutepetongo in?: America/Mexico_City.
Which country is San Francisco Tutepetongo in?: Mexico (MX).

Get this page as JSON

no auth

cURL 200 OK

$ curl https://api.cityapi.org/v1/cities/3519247

{
  "data": {
    "id": 3519247,
    "name": "San Francisco Tutepetongo",
    "ascii_name": "San Francisco Tutepetongo",
    "country_code": "MX",
    "population": 694,
    "elevation": null,
    "timezone_id": "America/Mexico_City",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 17.71611,
    "longitude": -96.88083
  }
}