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TINYAHUARCO

Pasco · PERU (PE) · 10.77°S / 76.28°W

19
ADM1 · ID GeoNames 3,927,420

Tinyahuarco is a city in Peru with a population of 5,066. It sits at -10.77/-76.28, runs on America/Lima, is 7 km from Shelby.

Population 5,066
Place Type Populated Place
Elevation n/a
Timezone America/Lima

All facts

fields
Country
Peru
Subdivision
Pasco
Coords
10.77°S / 76.28°W
UTC offset
-5
DST
Observed

Proximity

nearest 10 · within 50 km
SE Shelby Pasco 850 7.4 km
SE Vicco Pasco 0 9.2 km
N San Antonio de Rancas Pasco 0 9.4 km
N Yanacancha Pasco 24,105 11.5 km
N Cerro de Pasco Pasco 58,899 11.5 km
SE Ninacaca Pasco 0 19.6 km
NE La Quinua Pasco 831 19.8 km
N Atacocha Pasco 920 22.5 km
S Huayllay Pasco 0 27.9 km

FAQ

3 questions
What is the population of Tinyahuarco?
5,066 people, per GeoNames.
Which timezone is Tinyahuarco in?
America/Lima.
Which country is Tinyahuarco in?
Peru (PE).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/3927420

{
  "data": {
    "id": 3927420,
    "name": "Tinyahuarco",
    "ascii_name": "Tinyahuarco",
    "country_code": "PE",
    "population": 5066,
    "elevation": null,
    "timezone_id": "America/Lima",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": -10.76771,
    "longitude": -76.27523
  }
}
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