CERBĂL

Hunedoara County · ROMANIA (RO) · 45.78°N / 22.72°E

ADM1 · ID GeoNames 682,391

Cerbăl is a city in Romania with a population of 655. It sits at 45.78/22.72, runs on Europe/Bucharest, is 5 km from Lelese.

Population 655

Place Type District Capital

Elevation n/a

Timezone Europe/Bucharest

All facts

fields

Country: Romania
Subdivision: Hunedoara County
Coords: 45.78°N / 22.72°E
UTC offset: +2
DST: Observed

Proximity

nearest 10 · within 50 km

S Lelese Hunedoara County 505 5.7 km

SE Ghelari Hunedoara County 1,670 9.0 km

SW Bunila Hunedoara County 455 10.0 km

W Bătrâna Hunedoara County 172 10.4 km

NE Cârjiţi Hunedoara County 787 11.7 km

SE Topliţa Hunedoara County 870 12.3 km

E Răcăștia Hunedoara County 564 12.3 km

E Peştişu Mic Hunedoara County 1,272 13.1 km

N Leșnic Hunedoara County 502 14.7 km

E Hunedoara Hunedoara County 69,136 14.7 km

FAQ

3 questions

What is the population of Cerbăl?: 655 people, per GeoNames.
Which timezone is Cerbăl in?: Europe/Bucharest.
Which country is Cerbăl in?: Romania (RO).

Get this page as JSON

no auth

cURL 200 OK

$ curl https://api.cityapi.org/v1/cities/682391

{
  "data": {
    "id": 682391,
    "name": "Cerbăl",
    "ascii_name": "Cerbal",
    "country_code": "RO",
    "population": 655,
    "elevation": null,
    "timezone_id": "Europe/Bucharest",
    "feature_class": "P",
    "feature_code": "PPLA2",
    "latitude": 45.78333,
    "longitude": 22.71667
  }
}