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FELEACU

Cluj County · ROMANIA (RO) · 46.72°N / 23.62°E

13
ADM1 · ID GeoNames 678,355

Feleacu is a city in Romania with a population of 3,764. It sits at 46.72/23.62, runs on Europe/Bucharest, is 4 km from Vâlcele.

Population 3,764
Place Type District Capital
Elevation n/a
Timezone Europe/Bucharest

All facts

fields
Country
Romania
Subdivision
Cluj County
Coords
46.72°N / 23.62°E
UTC offset
+2
DST
Observed

Proximity

nearest 10 · within 50 km
SE Vâlcele Cluj County 939 4.4 km
E Gheorghieni Cluj County 1,226 5.5 km
N Cluj-Napoca Cluj County 286,598 5.7 km
SE Rediu Cluj County 795 7.0 km
S Micești Cluj County 560 8.2 km
SW Ciurila Cluj County 1,506 9.0 km
SE Aiton Cluj County 1,331 9.7 km
NE Dezmir Cluj County 1,140 9.8 km
W Floreşti Cluj County 7,397 9.9 km
E Pata Cluj County 600 10.0 km

Air access

nearby

FAQ

3 questions
What is the population of Feleacu?
3,764 people, per GeoNames.
Which timezone is Feleacu in?
Europe/Bucharest.
Which country is Feleacu in?
Romania (RO).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/678355

{
  "data": {
    "id": 678355,
    "name": "Feleacu",
    "ascii_name": "Feleacu",
    "country_code": "RO",
    "population": 3764,
    "elevation": null,
    "timezone_id": "Europe/Bucharest",
    "feature_class": "P",
    "feature_code": "PPLA2",
    "latitude": 46.71667,
    "longitude": 23.61667
  }
}
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