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FRUMUȘELU

Bacău County · ROMANIA (RO) · 46.28°N / 27.35°E

04
ADM1 · ID GeoNames 677,876

Frumușelu is a city in Romania with a population of 1,551. It sits at 46.28/27.35, runs on Europe/Bucharest, is 3 km from Țepoaia.

Population 1,551
Place Type Populated Place
Elevation n/a
Timezone Europe/Bucharest

All facts

fields
Country
Romania
Subdivision
Bacău County
Coords
46.28°N / 27.35°E
UTC offset
+2
DST
Observed

Proximity

nearest 10 · within 50 km
N Țepoaia Bacău County 572 3.9 km
SE Glăvăneşti Bacău County 3,760 3.9 km
W Căuia Bacău County 550 5.4 km
S Sârbi Bacău County 531 5.4 km
E Poiana Bacău County 520 5.5 km
N Motoşeni Bacău County 4,007 6.6 km
SW Negulești Bacău County 721 7.1 km
W Huruiești Bacău County 801 8.0 km
S Podu Turcului Bacău County 5,081 9.0 km
SE Căbești Bacău County 829 10.0 km

Air access

nearby

FAQ

3 questions
What is the population of Frumușelu?
1,551 people, per GeoNames.
Which timezone is Frumușelu in?
Europe/Bucharest.
Which country is Frumușelu in?
Romania (RO).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/677876

{
  "data": {
    "id": 677876,
    "name": "Frumușelu",
    "ascii_name": "Frumuselu",
    "country_code": "RO",
    "population": 1551,
    "elevation": null,
    "timezone_id": "Europe/Bucharest",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 46.27796,
    "longitude": 27.35203
  }
}
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