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ODOREU

Satu Mare County · ROMANIA (RO) · 47.80°N / 23.00°E

32
ADM1 · ID GeoNames 671,966

Odoreu is a city in Romania with a population of 4,765. It sits at 47.80/23.00, runs on Europe/Bucharest, is 3 km from Petin.

Population 4,765
Place Type District Capital
Elevation n/a
Timezone Europe/Bucharest

All facts

fields
Country
Romania
Subdivision
Satu Mare County
Coords
47.80°N / 23.00°E
UTC offset
+2
DST
Observed

Proximity

nearest 10 · within 50 km
SW Petin Satu Mare County 629 3.9 km
SE Culciu Mic Satu Mare County 3,941 5.0 km
NW Botiz Satu Mare County 4,779 5.3 km
SW Ambud Satu Mare County 999 5.3 km
W Păuleşti Satu Mare County 4,258 6.5 km
SE Culciu Mare Satu Mare County 773 6.7 km
NE Dumbrava Satu Mare County 1,019 7.8 km
E Băbășești Satu Mare County 695 7.9 km
SW Amați Satu Mare County 896 8.7 km
S Hrip Satu Mare County 608 8.8 km

Air access

nearby

FAQ

3 questions
What is the population of Odoreu?
4,765 people, per GeoNames.
Which timezone is Odoreu in?
Europe/Bucharest.
Which country is Odoreu in?
Romania (RO).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/671966

{
  "data": {
    "id": 671966,
    "name": "Odoreu",
    "ascii_name": "Odoreu",
    "country_code": "RO",
    "population": 4765,
    "elevation": null,
    "timezone_id": "Europe/Bucharest",
    "feature_class": "P",
    "feature_code": "PPLA2",
    "latitude": 47.8,
    "longitude": 23.0
  }
}
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