ŞELARU

Dâmbovița County · ROMANIA (RO) · 44.48°N / 25.30°E

ADM1 · ID GeoNames 667,429

Şelaru is a city in Romania with a population of 3,924. It sits at 44.48/25.30, runs on Europe/Bucharest, is 3 km from Fierbinți.

Population 3,924

Place Type District Capital

Elevation n/a

Timezone Europe/Bucharest

All facts

fields

Country: Romania
Subdivision: Dâmbovița County
Coords: 44.48°N / 25.30°E
UTC offset: +2
DST: Observed

Proximity

nearest 10 · within 50 km

N Fierbinți Dâmbovița County 1,755 3.6 km

E Glogoveanu Dâmbovița County 908 3.8 km

W Ştefan cel Mare Arges 2,632 4.8 km

E Sârbeni Teleorman County 1,740 6.7 km

NW Slobozia Arges 5,045 7.1 km

S Poeni Teleorman County 3,335 8.9 km

E Udeni Teleorman County 733 10.4 km

SW Negrenii de Sus Teleorman County 544 11.1 km

SW Negreni Teleorman County 734 11.1 km

S Siliştea Teleorman County 4,391 11.1 km

Air access

nearby

LRPT

Geamăna Airfield

Small airport

49.5 km

FAQ

3 questions

What is the population of Şelaru?: 3,924 people, per GeoNames.
Which timezone is Şelaru in?: Europe/Bucharest.
Which country is Şelaru in?: Romania (RO).

Get this page as JSON

no auth

cURL 200 OK

$ curl https://api.cityapi.org/v1/cities/667429

{
  "data": {
    "id": 667429,
    "name": "Şelaru",
    "ascii_name": "Selaru",
    "country_code": "RO",
    "population": 3924,
    "elevation": null,
    "timezone_id": "Europe/Bucharest",
    "feature_class": "P",
    "feature_code": "PPLA2",
    "latitude": 44.47667,
    "longitude": 25.29997
  }
}