TEIUȘU

Vâlcea County · ROMANIA (RO) · 45.09°N / 24.24°E

ADM1 · ID GeoNames 665,311

Teiușu is a city in Romania with a population of 526. It sits at 45.09/24.24, runs on Europe/Bucharest, is 2 km from Lunca.

Population 526

Place Type Section of City

Elevation n/a

Timezone Europe/Bucharest

All facts

fields

Country: Romania
Subdivision: Vâlcea County
Coords: 45.09°N / 24.24°E
UTC offset: +2
DST: Observed

Proximity

nearest 10 · within 50 km

E Lunca Vâlcea County 697 2.3 km

SW Gurișoara Vâlcea County 529 2.4 km

E Ocnița Vâlcea County 556 2.9 km

NE Priporu Vâlcea County 906 4.5 km

W Băile Govora Vâlcea County 2,862 4.5 km

N Păuşeşti-Măglaşi Vâlcea County 3,775 4.6 km

E Gura Suhașului Vâlcea County 1,513 4.7 km

N Coasta Vâlcea County 621 4.7 km

N Vlăduceni Vâlcea County 581 5.0 km

NW Buneşti Vâlcea County 2,620 5.2 km

FAQ

3 questions

What is the population of Teiușu?: 526 people, per GeoNames.
Which timezone is Teiușu in?: Europe/Bucharest.
Which country is Teiușu in?: Romania (RO).

Get this page as JSON

no auth

cURL 200 OK

$ curl https://api.cityapi.org/v1/cities/665311

{
  "data": {
    "id": 665311,
    "name": "Teiușu",
    "ascii_name": "Teiusu",
    "country_code": "RO",
    "population": 526,
    "elevation": null,
    "timezone_id": "Europe/Bucharest",
    "feature_class": "P",
    "feature_code": "PPLX",
    "latitude": 45.09273,
    "longitude": 24.23958
  }
}