INDIAN ROCKS BEACH

Florida · UNITED STATES (US) · 27.88°N / 82.85°W

ADM1 · ID GeoNames 4,159,675

Indian Rocks Beach is a city in United States with a population of 4,113. It sits at 27.88/-82.85, runs on America/New_York, is 1 km from Indian Shores.

Population 4,113

Place Type Populated Place

Elevation 0m

Timezone America/New_York

All facts

fields

Country: United States
Subdivision: Florida
Coords: 27.88°N / 82.85°W
UTC offset: -5
DST: Observed

Proximity

nearest 10 · within 50 km

S Indian Shores Florida 1,470 1.4 km

NE Harbor Bluffs Florida 2,860 4.4 km

NE Ridgecrest Florida 2,558 5.1 km

N Belleair Beach Florida 1,609 5.4 km

S Redington Shores Florida 2,205 5.9 km

NE Belleair Bluffs Florida 2,095 6.1 km

SE Seminole Florida 18,153 7.1 km

SE North Redington Beach Florida 1,463 7.2 km

NE Largo Florida 81,000 7.3 km

NE Belleair Florida 3,992 8.0 km

Air access

nearby

CLW

Clearwater Air Park

Small airport

14.5 km

PIE

St. Petersburg Clearwater International Airport

Large airport

16.6 km

SPG

Albert Whitted Airport

Small airport

25.2 km

MCF

MacDill Air Force Base

Medium airport

32.6 km

TPA

Tampa International Airport

Large airport

33.2 km

FAQ

3 questions

What is the population of Indian Rocks Beach?: 4,113 people, per GeoNames.
Which timezone is Indian Rocks Beach in?: America/New_York.
Which country is Indian Rocks Beach in?: United States (US).

Get this page as JSON

no auth

cURL 200 OK

$ curl https://api.cityapi.org/v1/cities/4159675

{
  "data": {
    "id": 4159675,
    "name": "Indian Rocks Beach",
    "ascii_name": "Indian Rocks Beach",
    "country_code": "US",
    "population": 4113,
    "elevation": 0,
    "timezone_id": "America/New_York",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 27.8753,
    "longitude": -82.85122
  }
}