LAKE ALFRED

Florida · UNITED STATES (US) · 28.09°N / 81.72°W

ADM1 · ID GeoNames 4,161,150

Lake Alfred is a city in United States with a population of 5,475. It sits at 28.09/-81.72, runs on America/New_York, is 7 km from Auburndale.

Population 5,475

Place Type Populated Place

Elevation 53m

Timezone America/New_York

All facts

fields

Country: United States
Subdivision: Florida
Coords: 28.09°N / 81.72°W
UTC offset: -5
DST: Observed

Proximity

nearest 10 · within 50 km

SW Auburndale Florida 15,035 7.1 km

SW Inwood Florida 6,403 7.3 km

S Winter Haven Florida 37,689 7.8 km

SW Jan-Phyl Village Florida 5,573 9.8 km

E Haines City Florida 22,807 10.5 km

SE Lake Hamilton Florida 1,346 10.8 km

S Eloise Florida 23,366 10.9 km

S Cypress Gardens Florida 8,917 11.3 km

SE Dundee Florida 4,090 12.8 km

S Eagle Lake Florida 2,474 13.0 km

Air access

nearby

GIF

Winter Haven Regional Airport - Gilbert Field

Small airport

4.4 km

BOW

Bartow Executive Airport

Small airport

17.5 km

LAL

Lakeland Linder International Airport

Medium airport

31.4 km

ISM

Kissimmee Gateway Airport

Medium airport

35.7 km

ZPH

Zephyrhills Municipal Airport

Small airport

45.1 km

FAQ

3 questions

What is the population of Lake Alfred?: 5,475 people, per GeoNames.
Which timezone is Lake Alfred in?: America/New_York.
Which country is Lake Alfred in?: United States (US).

Get this page as JSON

no auth

cURL 200 OK

$ curl https://api.cityapi.org/v1/cities/4161150

{
  "data": {
    "id": 4161150,
    "name": "Lake Alfred",
    "ascii_name": "Lake Alfred",
    "country_code": "US",
    "population": 5475,
    "elevation": 53,
    "timezone_id": "America/New_York",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 28.09196,
    "longitude": -81.72341
  }
}