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SELINSGROVE

Pennsylvania · UNITED STATES (US) · 40.80°N / 76.86°W

PA
ADM1 · ID GeoNames 5,211,411

Selinsgrove is a city in United States with a population of 5,792. It sits at 40.80/-76.86, runs on America/New_York, is 4 km from Hummels Wharf.

Population 5,792
Place Type Populated Place
Elevation 134m
Timezone America/New_York

All facts

fields
Country
United States
Subdivision
Pennsylvania
Coords
40.80°N / 76.86°W
UTC offset
-5
DST
Observed

Proximity

nearest 10 · within 50 km
NE Hummels Wharf Pennsylvania 1,353 4.3 km
NE Shamokin Dam Pennsylvania 1,706 6.6 km
SW Freeburg Pennsylvania 575 7.6 km
W Kreamer Pennsylvania 822 8.6 km
NE Sunbury Pennsylvania 9,652 9.1 km
S Port Trevorton Pennsylvania 769 10.2 km
NE Northumberland Pennsylvania 3,728 11.7 km
N Kapp Heights Pennsylvania 863 12.1 km
N Winfield Pennsylvania 900 12.3 km
NW New Berlin Pennsylvania 867 13.8 km

Air access

nearby

FAQ

3 questions
What is the population of Selinsgrove?
5,792 people, per GeoNames.
Which timezone is Selinsgrove in?
America/New_York.
Which country is Selinsgrove in?
United States (US).

Get this page as JSON

no auth
cURL 200 OK
$ curl https://api.cityapi.org/v1/cities/5211411

{
  "data": {
    "id": 5211411,
    "name": "Selinsgrove",
    "ascii_name": "Selinsgrove",
    "country_code": "US",
    "population": 5792,
    "elevation": 134,
    "timezone_id": "America/New_York",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 40.79897,
    "longitude": -76.86219
  }
}
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