SEYMOUR

Indiana · UNITED STATES (US) · 38.96°N / 85.89°W

ADM1 · ID GeoNames 4,264,617

Seymour is a city in United States with a population of 19,478. It sits at 38.96/-85.89, runs on America/Indiana/Indianapolis, is 13 km from Hayden.

Population 19,478

Place Type Populated Place

Elevation 184m

Timezone America/Indiana/Indianapolis

All facts

fields

Country: United States
Subdivision: Indiana
Coords: 38.96°N / 85.89°W
UTC offset: -5
DST: Observed

Proximity

nearest 10 · within 50 km

E Hayden Indiana 521 13.2 km

SW Brownstown Indiana 2,952 15.9 km

S Crothersville Indiana 1,597 18.1 km

NE Country Squire Lakes Indiana 3,571 18.6 km

N Elizabethtown Indiana 518 20.6 km

S Austin Indiana 4,295 23.4 km

E North Vernon Indiana 6,619 23.7 km

N Columbus Indiana 46,690 27.0 km

SW Medora Indiana 698 28.5 km

S Scottsburg Indiana 6,674 32.1 km

Air access

nearby

SER

Freeman Municipal Airport

Small airport

0.0 km

CLU

Columbus Municipal Airport

Medium airport

33.7 km

MDN

Madison Municipal Airport

Small airport

43.1 km

BFR

Virgil I Grissom Municipal Airport

Small airport

49.9 km

FAQ

3 questions

What is the population of Seymour?: 19,478 people, per GeoNames.
Which timezone is Seymour in?: America/Indiana/Indianapolis.
Which country is Seymour in?: United States (US).

Get this page as JSON

no auth

cURL 200 OK

$ curl https://api.cityapi.org/v1/cities/4264617

{
  "data": {
    "id": 4264617,
    "name": "Seymour",
    "ascii_name": "Seymour",
    "country_code": "US",
    "population": 19478,
    "elevation": 184,
    "timezone_id": "America/Indiana/Indianapolis",
    "feature_class": "P",
    "feature_code": "PPL",
    "latitude": 38.95922,
    "longitude": -85.89025
  }
}